E. Zhu
ATP
#462 / 100 pts
Seoul 2026
E. Zhu vs Y. Jeong - Seoul - 25 Oct 2026
E. Zhu vs Y. Jeong is listed under Seoul 2026 with score, status, set context, ranking signals and head-to-head information when available.
Finished
Seoul - Semi-finals
Surface
Sets
S1
S2
E. Zhu
4
4
Y. Jeong
6
6
Match answer summary
Seoul 2026Status
Finished
Winner
Y. Jeong
Round / surface
Seoul - Semi-finals
Odds signals
0 pre-match / 0 live
Ranking context
E. Zhu ATP #462; Y. Jeong ATP #1522
H2H meetings
1
Recent form
E. Zhu 2-3
E. Zhu vs Y. Jeong is a tennis match in Seoul 2026 (Seoul - Semi-finals). Status: Finished. Score: 0 - 2. Winner: Y. Jeong. Ranking context: E. Zhu ATP #462; Y. Jeong ATP #1522. H2H context: 1 known meetings. Recent form: E. Zhu 2-3. Odds rows: 0 pre-match / 0 live.
Match context
FinishedDate2026-10-25 05:05:00
TournamentSeoul 2026
RoundSeoul - Semi-finals
Surface-
StatusFinished
TourChallenger Men Singles
TierChallenger
WinnerY. Jeong
Point-by-pointYes
Match signals
set scoresScore contextYes
Set scoreYes
H2H contextYes
TournamentSeoul 2026
Pre-match odds rows0
Live odds rows0
H2H summary
VisibleTotal H2H1
Official H2H1
Exhibition H2H0
Latest meeting2026-10-25
Players
Player 1E. Zhu
Player 2Y. Jeong
Country
USA
/
South Korea
Ranking context
2Y. Jeong
ATP
#1522 / 4 pts
Latest H2H meetings
1| Date | Tournament | Match | Score | Winner |
|---|---|---|---|---|
| 2026-10-25 | Seoul | E. Zhu vs Y. Jeong | 0 - 2 | Y. Jeong |
Player profiles and stats
2E. Zhu
Y. Jeong
Point-by-point
20| Set | Game | Point | Score | Serve | Winner |
|---|---|---|---|---|---|
| - | - | 1 | 1 - 0 | - | - |
| - | - | 2 | 1 - 1 | - | - |
| - | - | 3 | 1 - 2 | - | - |
| - | - | 4 | 2 - 2 | - | - |
| - | - | 5 | 3 - 2 | - | - |
| - | - | 6 | 3 - 3 | - | - |
| - | - | 7 | 3 - 4 | - | - |
| - | - | 8 | 3 - 5 | - | - |
| - | - | 9 | 4 - 5 | - | - |
| - | - | 10 | 4 - 6 | - | - |
| - | - | 11 | 1 - 0 | - | - |
| - | - | 12 | 1 - 1 | - | - |
| - | - | 13 | 2 - 1 | - | - |
| - | - | 14 | 2 - 2 | - | - |
| - | - | 15 | 2 - 3 | - | - |
| - | - | 16 | 2 - 4 | - | - |
| - | - | 17 | 3 - 4 | - | - |
| - | - | 18 | 3 - 5 | - | - |
| - | - | 19 | 4 - 5 | - | - |
| - | - | 20 | 4 - 6 | - | - |
Tournament draw context
12| Order | Date | Round | Match | Score |
|---|---|---|---|---|
| 1 | 2026-10-25 | Seoul - Semi-finals | S. Imai vs K. Isomura | 2 - 1 |
| 2 | 2026-10-25 | Seoul - Semi-finals | A. Kachmazov vs D. J. Kim | 2 - 1 |
| 3 | 2026-10-25 | Seoul - Semi-finals | W. Shin vs T. J. Fancutt | 2 - 1 |
| 4 | 2026-10-25 | Seoul - Semi-finals | A. Ayeni vs U. Park | 1 - 2 |
| 5 | 2026-10-25 | Seoul - Semi-finals | Y. Chung vs A. Donski | 2 - 0 |
| 6 | 2026-10-25 | Seoul - Semi-finals | E. Zhu vs Y. Jeong | 0 - 2 |
| 7 | 2026-10-25 | Seoul - Semi-finals | M. H. Ko vs B. Zhukayev | 0 - 2 |
| 8 | 2026-10-25 | Seoul - Semi-finals | C. Langmo vs Y. Takahashi | 2 - 1 |
| 9 | 2026-10-25 | Seoul - Semi-finals | Je. Delaney vs S. Shin | 1 - 2 |
| 10 | 2026-10-25 | Seoul - Semi-finals | K. Matsuda vs G. J. Kim | 2 - 0 |
| 11 | 2026-10-25 | Seoul - Semi-finals | O. Jasika vs T. W. Kim | 2 - 0 |
| 12 | 2026-10-25 | Seoul - Semi-finals | Y. Kikuchi vs D. Sakellaridis | 2 - 1 |
Recent player form
6E. Zhu
2026-10-19
M. Purcell
L
2026-10-18
Y. Zeng
W
2026-10-14
E. Pleshivtsev
L
2026-10-08
A. Kachmazov
L
2026-10-06
K. Matsuda
W
Y. Jeong
2026-10-26
Y. Chung
-
Tennis match FAQ
Seoul 2026What tennis match details are shown here?
E. Zhu vs Y. Jeong is a tennis match in Seoul 2026 (Seoul - Semi-finals). Status: Finished. Score: 0 - 2. Winner: Y. Jeong. Ranking context: E. Zhu ATP #462; Y. Jeong ATP #1522. H2H context: 1 known meetings. Recent form: E. Zhu 2-3. Odds rows: 0 pre-match / 0 live.
Does this page include player form and ranking context?
Ranking context: E. Zhu ATP #462; Y. Jeong ATP #1522. Recent form: E. Zhu 2-3.
Are tennis odds and point-by-point details available?
Available tennis market rows: 0 pre-match / 0 live. Point-by-point rows are shown when the tennis read-model returns them for this match.
Why can some tennis match blocks be empty?
ScoreBob renders optional tennis blocks only when the parser read-model has enough reliable data for that match.