SCOREBOB
26.10.2026
M15 Luan 4 2026

K. Ogura vs M. Zhang - M15 Luan 4 - 30 Sep 2026

K. Ogura vs M. Zhang is listed under M15 Luan 4 2026 with score, status, set context, ranking signals and head-to-head information when available.
Finished M15 Luan 4 - 1/16-finals Surface
Sets S1 S2 K. Ogura 6 6 M. Zhang 0 2

Match answer summary

M15 Luan 4 2026
Status
Finished
Winner
K. Ogura
Round / surface
M15 Luan 4 - 1/16-finals
Odds signals
0 pre-match / 0 live
Ranking context
K. Ogura ATP #795; M. Zhang ATP #1475
Recent form
K. Ogura 3-2; M. Zhang 0-3
K. Ogura vs M. Zhang is a tennis match in M15 Luan 4 2026 (M15 Luan 4 - 1/16-finals). Status: Finished. Score: 2 - 0. Winner: K. Ogura. Ranking context: K. Ogura ATP #795; M. Zhang ATP #1475. Recent form: K. Ogura 3-2; M. Zhang 0-3. Odds rows: 0 pre-match / 0 live.

Match context

Finished
Date2026-09-30 05:30:00
TournamentM15 Luan 4 2026
RoundM15 Luan 4 - 1/16-finals
Surface-
StatusFinished
TourItf Men Singles
TierITF
WinnerK. Ogura
Point-by-pointYes

Match signals

set scores
Score contextYes
Set scoreYes
H2H contextNo
TournamentM15 Luan 4 2026
Pre-match odds rows0
Live odds rows0

H2H summary

No
Total H2H0
Official H2H0
Exhibition H2H0
Latest meeting-

Players

Japan Japan / China China
Player 1K. Ogura
Player 2M. Zhang
Country Japan Japan / China China

Ranking context

2

K. Ogura

ATP #795 / 36 pts

M. Zhang

ATP #1475 / 5 pts

Player profiles and stats

2
K. Ogura
Japan Japan
Stats rows: 0 · Finished matches: 28 · Tournaments: 17
M. Zhang
China China
Stats rows: 0 · Finished matches: 9 · Tournaments: 8

Point-by-point

14
Set Game Point Score Serve Winner
- - 1 1 - 0 - -
- - 2 2 - 0 - -
- - 3 3 - 0 - -
- - 4 4 - 0 - -
- - 5 5 - 0 - -
- - 6 6 - 0 - -
- - 7 0 - 1 - -
- - 8 1 - 1 - -
- - 9 1 - 2 - -
- - 10 2 - 2 - -
- - 11 3 - 2 - -
- - 12 4 - 2 - -
- - 13 5 - 2 - -
- - 14 6 - 2 - -

Tournament draw context

16
Order Date Round Match Score
1 2026-09-29 M15 Luan 4 - 1/16-finals R. Matsuda vs Z. Shao 2 - 0
2 2026-09-29 M15 Luan 4 - 1/16-finals J. Yamasaki vs M. Purcell 0 - 2
3 2026-09-29 M15 Luan 4 - 1/16-finals Z. Zhao vs M. Malaszszak 2 - 0
4 2026-09-30 M15 Luan 4 - 1/16-finals N. Barsukov vs T. Yamanaka 0 - 2
5 2026-09-30 M15 Luan 4 - 1/16-finals Z. Liu vs Y. Jin 0 - 2
6 2026-09-30 M15 Luan 4 - 1/16-finals M. Sasikumar vs Oh Chan-Yeong 0 - 2
7 2026-09-30 M15 Luan 4 - 1/16-finals Y. Tomida vs X. Han 2 - 0
8 2026-09-30 M15 Luan 4 - 1/16-finals K. Ogura vs M. Zhang 2 - 0
9 2026-09-30 M15 Luan 4 - 1/16-finals S. Muto vs R. Komagata 1 - 2
10 2026-09-30 M15 Luan 4 - 1/16-finals A. Susanto vs T. Ichikawa 0 - 2
11 2026-09-30 M15 Luan 4 - 1/16-finals J. Van Herzeele vs N. Beamish 2 - 0
12 2026-09-30 M15 Luan 4 - 1/16-finals J. Dembo vs I. Becroft 0 - 2
13 2026-09-30 M15 Luan 4 - 1/16-finals N. Ehrenschneider vs T. Masabayashi 2 - 0
14 2026-09-30 M15 Luan 4 - 1/16-finals Y. Taka vs W. Li 2 - 0
15 2026-09-30 M15 Luan 4 - 1/16-finals K. Wang vs J. Chiu 2 - 0
16 2026-09-30 M15 Luan 4 - 1/16-finals X. D. Chen vs D. J. Kim 0 - 2

Recent player form

10

K. Ogura

2026-10-24 M. Janvier L
2026-10-23 A. Habib W
2026-10-22 Han Seon Yong W
2026-10-21 A. Watanabe Eriksson W
2026-10-04 Y. Kikuchi L

M. Zhang

2026-10-20 K. S. Chen L
2026-09-16 C. Ferguson L
2026-09-02 Z. Yang -
2026-07-15 Z. Zhao -
2026-07-01 M. Rifqi Fitriadi L

Tennis match FAQ

M15 Luan 4 2026

What tennis match details are shown here?

K. Ogura vs M. Zhang is a tennis match in M15 Luan 4 2026 (M15 Luan 4 - 1/16-finals). Status: Finished. Score: 2 - 0. Winner: K. Ogura. Ranking context: K. Ogura ATP #795; M. Zhang ATP #1475. Recent form: K. Ogura 3-2; M. Zhang 0-3. Odds rows: 0 pre-match / 0 live.

Does this page include player form and ranking context?

Ranking context: K. Ogura ATP #795; M. Zhang ATP #1475. Recent form: K. Ogura 3-2; M. Zhang 0-3.

Are tennis odds and point-by-point details available?

Available tennis market rows: 0 pre-match / 0 live. Point-by-point rows are shown when the tennis read-model returns them for this match.

Why can some tennis match blocks be empty?

ScoreBob renders optional tennis blocks only when the parser read-model has enough reliable data for that match.