W15 Maanshan 7 2026
V. Panshina vs S. H. Jang - W15 Maanshan 7 - 08 Oct 2026
V. Panshina vs S. H. Jang is listed under W15 Maanshan 7 2026 with score, status, set context, ranking signals and head-to-head information when available.
Finished
W15 Maanshan 7 - 1/8-finals
Surface
Sets
S1
S2
V. Panshina
6
6
S. H. Jang
1
2
Match answer summary
W15 Maanshan 7 2026
Round / surface
W15 Maanshan 7 - 1/8-finals
Odds signals
0 pre-match / 0 live
Ranking context
V. Panshina WTA #372
Recent form
V. Panshina 3-2; S. H. Jang 3-2
V. Panshina vs S. H. Jang is a tennis match in W15 Maanshan 7 2026 (W15 Maanshan 7 - 1/8-finals). Status: Finished. Score: 2 - 0. Winner: V. Panshina. Ranking context: V. Panshina WTA #372. H2H context: 1 known meetings. Recent form: V. Panshina 3-2; S. H. Jang 3-2. Odds rows: 0 pre-match / 0 live.
Match context
Finished
Date2026-10-08 04:00:00
TournamentW15 Maanshan 7 2026
RoundW15 Maanshan 7 - 1/8-finals
Surface-
StatusFinished
TourItf Women Singles
TierITF
WinnerV. Panshina
Point-by-pointYes
Match signals
set scores
Score contextYes
Set scoreYes
H2H contextYes
TournamentW15 Maanshan 7 2026
Pre-match odds rows0
Live odds rows0
H2H summary
Visible
Total H2H1
Official H2H1
Exhibition H2H0
Latest meeting2026-10-08
Players
WO
World
/
UN
Unknown country
Player 1V. Panshina
Player 2S. H. Jang
Country
WO
World
/
UN
Unknown country
Ranking context
1
V. Panshina
WTA
#372 / 172 pts
S. H. Jang
Ranking
-
Latest H2H meetings
1
| Date |
Tournament |
Match |
Score |
Winner |
| 2026-10-08 |
W15 Maanshan 7 |
S. H. Jang vs V. Panshina |
2 - 0 |
V. Panshina |
Player profiles and stats
2
VP
V. Panshina
WO
World
Stats rows: 0
· Finished matches: 22
· Tournaments: 9
SH
S. H. Jang
TE
Tennis
Stats rows: 0
· Finished matches: 7
· Tournaments: 4
Point-by-point
15
| Set |
Game |
Point |
Score |
Serve |
Winner |
| - |
- |
1 |
1 - 0 |
- |
- |
| - |
- |
2 |
2 - 0 |
- |
- |
| - |
- |
3 |
3 - 0 |
- |
- |
| - |
- |
4 |
4 - 0 |
- |
- |
| - |
- |
5 |
5 - 0 |
- |
- |
| - |
- |
6 |
5 - 1 |
- |
- |
| - |
- |
7 |
6 - 1 |
- |
- |
| - |
- |
8 |
1 - 0 |
- |
- |
| - |
- |
9 |
2 - 0 |
- |
- |
| - |
- |
10 |
3 - 0 |
- |
- |
| - |
- |
11 |
4 - 0 |
- |
- |
| - |
- |
12 |
4 - 1 |
- |
- |
| - |
- |
13 |
4 - 2 |
- |
- |
| - |
- |
14 |
5 - 2 |
- |
- |
| - |
- |
15 |
6 - 2 |
- |
- |
Tournament draw context
8
| Order |
Date |
Round |
Match |
Score |
| 17 |
2026-10-08 |
W15 Maanshan 7 - 1/8-finals |
Y. Chen vs A. Yang |
2 - 1 |
| 18 |
2026-10-08 |
W15 Maanshan 7 - 1/8-finals |
F. Franchi vs Y. Wang |
0 - 2 |
| 19 |
2026-10-08 |
W15 Maanshan 7 - 1/8-finals |
V. Panshina vs S. H. Jang |
2 - 0 |
| 20 |
2026-10-08 |
W15 Maanshan 7 - 1/8-finals |
X. Tang vs J. Wang |
0 - 2 |
| 21 |
2026-10-08 |
W15 Maanshan 7 - 1/8-finals |
M. Guo vs D. Egorova |
0 - 2 |
| 22 |
2026-10-08 |
W15 Maanshan 7 - 1/8-finals |
G. Jang vs F. A. Lin |
0 - 2 |
| 23 |
2026-10-08 |
W15 Maanshan 7 - 1/8-finals |
M. Shikhanova vs J. Zhang |
0 - 2 |
| 24 |
2026-10-08 |
W15 Maanshan 7 - 1/8-finals |
Y. Hou vs A. Yuneva |
2 - 0 |
Recent player form
10
V. Panshina
2026-10-24
D. Khomutsianskaya
L
2026-10-23
W. Zheng
W
2026-10-22
C. Muramatsu
W
2026-10-21
Z. Bai
W
2026-10-10
D. Egorova
L
S. H. Jang
2026-10-06
E. Kuznetsova
W
2026-09-30
K. Ren
L
2026-09-04
K. Yodpetch
L
2026-09-03
S. J. Jang
W
2026-09-02
N. Hanatani
W
Tennis match FAQ
W15 Maanshan 7 2026
What tennis match details are shown here?
V. Panshina vs S. H. Jang is a tennis match in W15 Maanshan 7 2026 (W15 Maanshan 7 - 1/8-finals). Status: Finished. Score: 2 - 0. Winner: V. Panshina. Ranking context: V. Panshina WTA #372. H2H context: 1 known meetings. Recent form: V. Panshina 3-2; S. H. Jang 3-2. Odds rows: 0 pre-match / 0 live.
Does this page include player form and ranking context?
Ranking context: V. Panshina WTA #372. Recent form: V. Panshina 3-2; S. H. Jang 3-2.
Are tennis odds and point-by-point details available?
Available tennis market rows: 0 pre-match / 0 live. Point-by-point rows are shown when the tennis read-model returns them for this match.
Why can some tennis match blocks be empty?
ScoreBob renders optional tennis blocks only when the parser read-model has enough reliable data for that match.