M15 Luan 4 2026
M. Sasikumar vs Oh Chan-Yeong - M15 Luan 4 - 30 Sep 2026
M. Sasikumar vs Oh Chan-Yeong is listed under M15 Luan 4 2026 with score, status, set context, ranking signals and head-to-head information when available.
Finished
M15 Luan 4 - 1/16-finals
Surface
Sets
S1
S2
M. Sasikumar
4
3
Oh Chan-Yeong
6
6
Match answer summary
M15 Luan 4 2026
Round / surface
M15 Luan 4 - 1/16-finals
Odds signals
0 pre-match / 0 live
Ranking context
M. Sasikumar ATP #741; Oh Chan-Yeong ATP #963
Recent form
M. Sasikumar 2-3; Oh Chan-Yeong 1-4
M. Sasikumar vs Oh Chan-Yeong is a tennis match in M15 Luan 4 2026 (M15 Luan 4 - 1/16-finals). Status: Finished. Score: 0 - 2. Winner: Oh Chan-Yeong. Ranking context: M. Sasikumar ATP #741; Oh Chan-Yeong ATP #963. Recent form: M. Sasikumar 2-3; Oh Chan-Yeong 1-4. Odds rows: 0 pre-match / 0 live.
Match context
Finished
Date2026-09-30 04:00:00
TournamentM15 Luan 4 2026
RoundM15 Luan 4 - 1/16-finals
Surface-
StatusFinished
TourItf Men Singles
TierITF
WinnerOh Chan-Yeong
Point-by-pointNo
Match signals
set scores
Score contextYes
Set scoreYes
H2H contextNo
TournamentM15 Luan 4 2026
Pre-match odds rows0
Live odds rows0
H2H summary
No
Total H2H0
Official H2H0
Exhibition H2H0
Latest meeting-
Players
IN
India
/
SO
South Korea
Player 1M. Sasikumar
Player 2Oh Chan-Yeong
Country
IN
India
/
SO
South Korea
Ranking context
2
M. Sasikumar
ATP
#741 / 42 pts
Oh Chan-Yeong
ATP
#963 / 22 pts
Player profiles and stats
2
MS
M. Sasikumar
IN
India
Stats rows: 0
· Finished matches: 17
· Tournaments: 11
CO
Chan-Yeong Oh
SO
South Korea
Stats rows: 0
· Finished matches: 19
· Tournaments: 10
Tournament draw context
16
| Order |
Date |
Round |
Match |
Score |
| 1 |
2026-09-29 |
M15 Luan 4 - 1/16-finals |
R. Matsuda vs Z. Shao |
2 - 0 |
| 2 |
2026-09-29 |
M15 Luan 4 - 1/16-finals |
J. Yamasaki vs M. Purcell |
0 - 2 |
| 3 |
2026-09-29 |
M15 Luan 4 - 1/16-finals |
Z. Zhao vs M. Malaszszak |
2 - 0 |
| 4 |
2026-09-30 |
M15 Luan 4 - 1/16-finals |
N. Barsukov vs T. Yamanaka |
0 - 2 |
| 5 |
2026-09-30 |
M15 Luan 4 - 1/16-finals |
Z. Liu vs Y. Jin |
0 - 2 |
| 6 |
2026-09-30 |
M15 Luan 4 - 1/16-finals |
M. Sasikumar vs Oh Chan-Yeong |
0 - 2 |
| 7 |
2026-09-30 |
M15 Luan 4 - 1/16-finals |
Y. Tomida vs X. Han |
2 - 0 |
| 8 |
2026-09-30 |
M15 Luan 4 - 1/16-finals |
K. Ogura vs M. Zhang |
2 - 0 |
| 9 |
2026-09-30 |
M15 Luan 4 - 1/16-finals |
S. Muto vs R. Komagata |
1 - 2 |
| 10 |
2026-09-30 |
M15 Luan 4 - 1/16-finals |
A. Susanto vs T. Ichikawa |
0 - 2 |
| 11 |
2026-09-30 |
M15 Luan 4 - 1/16-finals |
J. Van Herzeele vs N. Beamish |
2 - 0 |
| 12 |
2026-09-30 |
M15 Luan 4 - 1/16-finals |
J. Dembo vs I. Becroft |
0 - 2 |
| 13 |
2026-09-30 |
M15 Luan 4 - 1/16-finals |
N. Ehrenschneider vs T. Masabayashi |
2 - 0 |
| 14 |
2026-09-30 |
M15 Luan 4 - 1/16-finals |
Y. Taka vs W. Li |
2 - 0 |
| 15 |
2026-09-30 |
M15 Luan 4 - 1/16-finals |
K. Wang vs J. Chiu |
2 - 0 |
| 16 |
2026-09-30 |
M15 Luan 4 - 1/16-finals |
X. D. Chen vs D. J. Kim |
0 - 2 |
Recent player form
10
M. Sasikumar
2026-10-21
R. Matsuda
L
2026-10-08
N. Ehrenschneider
L
2026-10-07
B. Butulija
W
2026-09-26
A. Kachmazov
L
2026-09-25
Oh Chan-Yeong
W
Oh Chan-Yeong
2026-10-01
K. Wang
L
2026-09-25
M. Sasikumar
L
2026-09-16
L. Borg
L
2026-09-10
H. Shiraishi
L
2026-09-09
T. Matsui
W
Tennis match FAQ
M15 Luan 4 2026
What tennis match details are shown here?
M. Sasikumar vs Oh Chan-Yeong is a tennis match in M15 Luan 4 2026 (M15 Luan 4 - 1/16-finals). Status: Finished. Score: 0 - 2. Winner: Oh Chan-Yeong. Ranking context: M. Sasikumar ATP #741; Oh Chan-Yeong ATP #963. Recent form: M. Sasikumar 2-3; Oh Chan-Yeong 1-4. Odds rows: 0 pre-match / 0 live.
Does this page include player form and ranking context?
Ranking context: M. Sasikumar ATP #741; Oh Chan-Yeong ATP #963. Recent form: M. Sasikumar 2-3; Oh Chan-Yeong 1-4.
Are tennis odds and point-by-point details available?
Available tennis market rows: 0 pre-match / 0 live. Point-by-point rows are shown when the tennis read-model returns them for this match.
Why can some tennis match blocks be empty?
ScoreBob renders optional tennis blocks only when the parser read-model has enough reliable data for that match.